solve this circle equation?

Determine whether the equation represents a circle, if the equation represents a circle, find the center and radius.

x2 + 2x + y2 - 4y = 5


its really appreciated

Kaila G2007-10-17T10:41:31Z

Favorite Answer

x^2 + 2x + 1 -1 + y^2 - 4y + 2 - 2 = 5

(x+1)^2 + (y-2)^2 = 5 +2+1 = 8

center = -1, 2
radius = sqrt 8

Anonymous2007-10-17T10:43:09Z

x^2 + 2x + y^2 - 4y = 5
(x + 1)^2 + (y - 2)^2 = 5 + 1 + 4 = 10
(x + 1)^2 + (y - 2)^2 = 10

gzlakewood@sbcglobal.net2007-10-17T10:59:06Z

Using the TI-83 and graphing, the ans. is no.

Formula for a circle at the center of a Cartesian plane is:

x^2 + y^2 = r^2

The center of the circle is ( 0,0) ordered pair on the graph.