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solve this circle equation?
Determine whether the equation represents a circle, if the equation represents a circle, find the center and radius.
x2 + 2x + y2 - 4y = 5
its really appreciated
3 Answers
- 1 decade agoFavorite Answer
x^2 + 2x + 1 -1 + y^2 - 4y + 2 - 2 = 5
(x+1)^2 + (y-2)^2 = 5 +2+1 = 8
center = -1, 2
radius = sqrt 8
- Anonymous1 decade ago
x^2 + 2x + y^2 - 4y = 5
(x + 1)^2 + (y - 2)^2 = 5 + 1 + 4 = 10
(x + 1)^2 + (y - 2)^2 = 10
- 1 decade ago
Using the TI-83 and graphing, the ans. is no.
Formula for a circle at the center of a Cartesian plane is:
x^2 + y^2 = r^2
The center of the circle is ( 0,0) ordered pair on the graph.
Source(s): Gzman
