any one pls solve this?
Find the derivative of
f (x) = sin 3x^2 / (3x+1)^2
thanks in advance for ur help
Scarlet Manuka
Favorite Answer
Hope you like your chain rule...
f'(x) = [(cos 3x^2) (6x) (3x+1)^2 - (sin 3x^2) (2) (3x+1) (3)] / (3x+1)^4
= [6x (3x+1) cos 3x^2 - 6 sin 3x^2] / (3x+1)^3
j_kkachi
If f(x) = g(x) / h(x)
then f'(x) = [g'(x) h(x) - g(x) h'(x)] / h^2 (x)