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Dr Virus
Dr Virus asked in Science & MathematicsMathematics · 1 decade ago

any one pls solve this?

Find the derivative of

f (x) = sin 3x^2 / (3x+1)^2

thanks in advance for ur help

2 Answers

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  • Scarlet Manuka
    Lv 7
    1 decade ago
    Favorite Answer

    Hope you like your chain rule...

    f'(x) = [(cos 3x^2) (6x) (3x+1)^2 - (sin 3x^2) (2) (3x+1) (3)] / (3x+1)^4

    = [6x (3x+1) cos 3x^2 - 6 sin 3x^2] / (3x+1)^3

  • j_kkachi
    1 decade ago

    If f(x) = g(x) / h(x)

    then f'(x) = [g'(x) h(x) - g(x) h'(x)] / h^2 (x)

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