The answer is 2+log(base5)X. Can somebody explain this please and if they know a website that explains this that would be helpful too, thanks.
Okay nevermind I figured it out, thanks for looking though. IF there is still any good logarithm help sites, could you please put them down, it would be much appreciated.
mohanrao d
Favorite Answer
log[5]25x
=>log[5]25 + log[5] x (since log ab = log a + logb)
=>log[5]5^2 + log[5]x
=>2log[5]5 + log[5]x (since loga^b = b log a)
=>2 + log[5]x (since log of any number to the base of same
number = 1)
Como
Let log be understood as log to base 5 :-
log (25 X) = log 25 + log X
log (25X) = 2 + log X
Joe L
Remember that when you multiply numbers by one another, you ADD their logs.
For example, Log (base 2) 4 = 2
Log (base 2) 8 = 3
Log (base 2)4X8 = Log(base 2)32 = 5
So you can "take your logs apart" and express them as follows:
Log(base 5)25X = Log(base 5) X + Log(base 5) 25
But
Log(base 5)25 = 2
So the answer is
2 + Log(base 5)X
norman
use the law of log addition
Log nm = log m + log n
log25x = log 25 + log x
log (base 5)25 = log (base 5) 5^2
use the law of log muliplication
Log m^n = n log m
log(base 5)5^2 = 2 log(base 5)5
log(base 5)5 = 1 so that is your ans.
Anonymous
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