i dk wat im doin?

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If you want to write the equation in point slope form, you have to write it as y=mx +b where m is the slope and b is the Yintercept.
So you already have... y= 3x+b

There is two ways you can do this:
1) Plot the point (-2,1) on the graph, and do the slope (rise over run which in this case would be moving up 3 units and to the right one) and plot those points until you intercept the Y axis. Whatever number that is, you can plug into b and get your equation of the line.

2) Since you already have the point and the slope, you can plug the point and the slope into the point-slope formula and solve for b(the y intercept).
So do 1=3(-2)+b and solve for b. Once you get the answer for b, rewrite the equation by only replacing the m and b and you have the point slope equation of your line!

**I do not believe in just giving the answer so that you understand how to do the problem, but you can email me the answer and ill tell you if you are correct! I check my email all the time....Show more

The point-slope formula is y-a=m(x+b)

You can find the equation if you have a point (a,b) and the slope (m).

So point (a,b) is (-2,1) and the slope (m) is 3.

Now you plug it in to the formula
y-(-2)=3(x+1)
y+2=3(x+1)--> is the answer...Show more

point slope form is y-y1 =m(x-x1)
(x1,y1) is a specific point here (-2,1)
m is the slope, here m=3:
y-1 =3(x - -2)
y-1 =3(x+2)...Show more