Algebra Advanced Exponents, tricky, first right answer 10pts?

Question

Asked this before but had a bad link, sorry

I'm just testing yahoo answers to see who here actually knows what they're talking about (at least in higher algebra)

Here's a link to a moderately hard advanced algebra problem, it can be tricky if you think you know what your talking about when you don't. It basically focuses on people's understanding of exponents.

http://img146.imageshack.us/img146/9964/guessgw9.png


I'll post an answer soon enough, Go for it!


I just don't like people posting answers to other questions when they don't understand the concepts

I'm getting an answer from this question even if its not the mathematical answer

nina1930 · Accepted Answer

2 x (2 ^2k + 2 ^2k) ^2
= 2 x ( (4^k) ^2 + 2 (4^k)(4^k) + (4^k)^2)
= 2 x (4^2k + 2(4^2k) + 4^2k)
 = 2 x 4^2k (1 +2+1+)
= 2 x 4^2k (4)
= 2x 2^4k x 2^2
= 2^1+4k+2
 = 2^4k+3

I wish I did it right.:)P

Dan C.... · Answer

Easy use logs, Log base 4k+4K, 4 then that equals log base 4k+4k to the x over 2 is equal to two. You could use base change to simplify it further but I dunno how simplified you want it. Dude you asked to simplify it and I used my knowledge in calculus. This is the calculus method of simplifying exponents. Logs are exponents or at least have similar traits.

Akilesh - Internet Undertaker · Answer

2(4^k + 4^k)^2
= 2*[2(4^k)]^2
= 2[4(4^2k)]
= 2[4^(2k + 1)]
= 2[2^(4k + 2)]
= 2^(4k + 3)

I didn't even look at the answer.

kellygrl6441 · Answer

8(16^k)

Verify: If k = 5
2(4^5 + 4^5)^2 = 8(16^5)
8,388,608 = 8,388608

rose1s · Answer

Question::: : 2(4^K + 4^K)^2 ------------- (1)
Solution :::: :
= 2( 2*4K)^2
= 2( 2^2*4^2K)
= 2^3 * 4^2K
= 2^3 * (2^2)^2K
= 2^3 * 2^4K
= 2^(3+4K)---------------------(2) ANSWER
Proof ::::
In eqn 1 Substitute K=2------------ 2048
In eqn 2 Substitue K=2------------ 2048
Tats it…..

Algebra Advanced Exponents, tricky, first right answer 10pts?

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