I am missing a step with this linear algebra problem, please assist. 15-6g+4g= -8 please solve for g thanks?

well I have 2 problems i need help with i seem to be missing something.
Problem #1 15-6g+4g= -8 I have to solve for g and show my work
Problem #2 -6+3/5x=24/5 I have to solve for x and show work.
please assist I have been trying to solve these for over an hour i keep missing a key step in both of them.

An ESL Learner2009-01-16T01:19:27Z

Favorite Answer

1)
15 - 6g + 4g = -8
-6g + 4g = -8 - 15
-2g = -23
g = -23/-2
g = 23/2 (11.5)

2)
-6 + 3/5(x) = 24/5
3x/5 = 6 + 24/5
3x = 5(6 + 24/5)
3x = 30 + 24
x = 54/3
x = 18

Joseph W2009-01-16T00:06:41Z

Problem 1

15-6g+4g=-8
-2g=-8-15 (subtract 15)
-2g = -23
2g= 23 (multiply by -1)
g = 11.5

Problem 2

-6 + 3/5x = 24/5
3/5x= 24/5 + 6 (take 6 over)
3/5x= 54/5 (6 = 30/5 and then you add)
x = 18 (divide by [3/5])

Midnight Train2009-01-16T00:17:10Z

1) Things get tricky going into the negative like this one. Just be careful with negatives. :o)

Combine like variables.
15 - 6g + 4g = -8 --->> 15 - 2g = -8

Subtract 15 from both sides.
15 - 15 - 2g = -8 - 15 --->> -2g = -23

Divide both sides by -2
(-2g) / 2 = (-23) / 2 --->> g = 11.5 (positive, not negative)


2) -6 + 3/5x = 24/5 First thing I would do is get rid of those fractions by multiplying both entire sides of the equation by 5.

5* (-6 + 3/5x) = (24/5) * 5 ----->> -30 + 15x = 120

Add 30 to both sides to get x by itself.
-30 + 30 + 15x = 120 + 30 --->> 15x = 150

Divide both sides by 15.
(15x) / 15 = (150) / 15 --->> x = 10

ViNi2009-01-16T01:02:36Z

Question 1:

-2g=-8-15
-2g=-23
g=-23/-2
g=11.5