I am missing a step with this linear algebra problem, please assist. 15-6g+4g= -8 please solve for g thanks?

1)

15 - 6g + 4g = -8

-6g + 4g = -8 - 15

-2g = -23

g = -23/-2

g = 23/2 (11.5)

2)

-6 + 3/5(x) = 24/5

3x/5 = 6 + 24/5

3x = 5(6 + 24/5)

3x = 30 + 24

x = 54/3

x = 18

Problem 1

15-6g+4g=-8

-2g=-8-15 (subtract 15)

-2g = -23

2g= 23 (multiply by -1)

g = 11.5

Problem 2

-6 + 3/5x = 24/5

3/5x= 24/5 + 6 (take 6 over)

3/5x= 54/5 (6 = 30/5 and then you add)

x = 18 (divide by [3/5])

1) Things get tricky going into the negative like this one. Just be careful with negatives. :o)

Combine like variables.

15 - 6g + 4g = -8 --->> 15 - 2g = -8

Subtract 15 from both sides.

15 - 15 - 2g = -8 - 15 --->> -2g = -23

Divide both sides by -2

(-2g) / 2 = (-23) / 2 --->> g = 11.5 (positive, not negative)

2) -6 + 3/5x = 24/5 First thing I would do is get rid of those fractions by multiplying both entire sides of the equation by 5.

5* (-6 + 3/5x) = (24/5) * 5 ----->> -30 + 15x = 120

Add 30 to both sides to get x by itself.

-30 + 30 + 15x = 120 + 30 --->> 15x = 150

Divide both sides by 15.

(15x) / 15 = (150) / 15 --->> x = 10

Question 1:

-2g=-8-15

-2g=-23

g=-23/-2

g=11.5