can you solve this equation?

2a^2=7a

thanks!

Jerome J2009-02-09T18:25:35Z

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2a² = 7a
2a² - 7a = 0
a(2a - 7) = 0
a = 0
(2a - 7) = 0
2a = 7
a = 7/2
a = {0, 7/2}

Anonymous2009-02-09T18:28:39Z

I am assuming you are just learning factoring. First subtract the 7a from the left to the right side. The quation now looks like: 2a^2 - 7a = 0. At this point, factor out one 'a' from each term. The equation looks like:
a(2a - 7) = 0. There are two possible answer to this problem. Notice that if either a or 2a - 7 is equal to 0, the equation is satisfied. So, now there are 2 mini equations. the first is a = 0, and 2a - 7 = 0. So solve each, the first is already done, the second's answer is a = 7/2. Both are correct

ajfrederick98672009-02-09T18:27:13Z

First get the term you're solving for on one side, so divide each side by a:

(2a^2)/a=(7a)/a

Now we have the equation 2a=7, and we want to get a by itself, so you divide each side by 2

(2a)/2=7/2

and we get the result

a=7/2

josbian2009-02-09T18:26:37Z

2a^2 = 7a
2a^2/a = 7
2a = 7
a = 7/2

Anonymous2009-02-09T18:24:35Z

2a²-7a=0
a(2a-7)=0
a=0 or 2a-7=0
a=0, 7/2

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