Among 2598960 possible 5-card poker hands from a standard 52-card deck, how many contain the folowing cards?
cards of more than one suit (compliment of "all the same suit")
help!
cards of more than one suit (compliment of "all the same suit")
help!
MathMan TG
Favorite Answer
Choose a card, it will be of some suit.
Chances of next card being same suit: 12 / 51
Next again: 11/50
Next: 10/49
Last: 9/48
12 * 11 * 10 * 9 / (51 * 50 * 49 * 48) =
11880 / 5997600 = .0019807 ... in poker terms 0.2% chance of a flush
Complementary probability = .99802 ... 99.802% chance of a non-flush,
i.e. more than one suit represented in 5 cards drawn at random
- - - If you want to use the given information:
13 C 5 = 5148 * 4 = 20592 / 2598960 to get the same result.
(Sets of 5 cards of any one suit * 4 suits)
.
hsu4derek
easy. the prob to draw all the same suit is (13c5*39c0)/52c5
that is to pick one suite. you have four suites, so the answer times 4
that gives you 0.001981
compliment that is 0.998