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Among 2598960 possible 5-card poker hands from a standard 52-card deck, how many contain the folowing cards?

cards of more than one suit (compliment of "all the same suit")

help!

2 Answers

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  • 1 decade ago
    Favorite Answer

    Choose a card, it will be of some suit.

    Chances of next card being same suit: 12 / 51

    Next again: 11/50

    Next: 10/49

    Last: 9/48

    12 * 11 * 10 * 9 / (51 * 50 * 49 * 48) =

    11880 / 5997600 = .0019807 ... in poker terms 0.2% chance of a flush

    Complementary probability = .99802 ... 99.802% chance of a non-flush,

    i.e. more than one suit represented in 5 cards drawn at random

    - - - If you want to use the given information:

    13 C 5 = 5148 * 4 = 20592 / 2598960 to get the same result.

    (Sets of 5 cards of any one suit * 4 suits)

    .

  • 1 decade ago

    easy. the prob to draw all the same suit is (13c5*39c0)/52c5

    that is to pick one suite. you have four suites, so the answer times 4

    that gives you 0.001981

    compliment that is 0.998

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