Factor x^4 + X^3 -X2 -X?
show work please. Is this prime or can i use diff/sum of cubes? I don't remember this stuff.
I realize the x factors out (GCF), but after that, is there any way to factor the problem?
show work please. Is this prime or can i use diff/sum of cubes? I don't remember this stuff.
I realize the x factors out (GCF), but after that, is there any way to factor the problem?
Anonymous
Favorite Answer
(x+1)(x^3-x) = x(x+1)^2 (x-1)
<3
X(X^3 + X^2 - X)
pittisit43
x(x^3 + x^2 - x - 1)
Anonymous
x^4 + x^3 - x^2 - x.
= x^3(x + 1) - x(x + 1)
= (x + 1) (x^3 -x)
= (x + 1) x(x^2 - 1)
= x(x + 1)(x - 1)(x + 1).
I hope that's right =S too much factoring.
Nor Aswani M
x^4 + x^3 - x^2 - x.
= x^3(x + 1) - x(x + 1)
= (x + 1) (x^3 -x)
= (x + 1) x(x^2 - 1)
= x(x + 1)(x - 1)(x + 1).
i think this should be the best answer..