Factor x^4 + X^3 -X2 -X?

(x+1)(x^3-x) = x(x+1)^2 (x-1)

X(X^3 + X^2 - X)

x(x^3 + x^2 - x - 1)

x^4 + x^3 - x^2 - x.

= x^3(x + 1) - x(x + 1)

= (x + 1) (x^3 -x)

= (x + 1) x(x^2 - 1)

= x(x + 1)(x - 1)(x + 1).

I hope that's right =S too much factoring.

x^4 + x^3 - x^2 - x.

= x^3(x + 1) - x(x + 1)

= (x + 1) (x^3 -x)

= (x + 1) x(x^2 - 1)

= x(x + 1)(x - 1)(x + 1).

i think this should be the best answer..

To factor x^4 + X^3 -X2 -X you will have to group them together. Since none of these have anthing in common, we'll group the ones that are next to eachother with eachother.

(x^4 + x³) + (-x²-x)

Now we need to factor out whatever is in common with the ones in parenthesis. The first group has three x's in common, and the second group has one NEGATIVE x in common.

x³(x+1) -x(x+1)

Now I join together x³ and -x, and the two (x+1)'s.

(x³-x)(x+1) is your answer!!

b is -5. Thank goodness for long division. You can check is by multiplying (x-1) by (x4 + 2x3 + 3x2 + 4x + 5) and you'll get (x5 + x4 + x3 + x2 + x - 5) leaving b as -5.

yeah its really easyy

youu put the GCF outside the parenthsis and divide

i think the answer is x^4 because x^3+x^4=x^7 then you could add -x and -2x and get - 3x which would thus get x^4 and positve was bigger so it would stay positive

(x^2-1)(x+1)

its right, i promise. i have my algebra book here and we have selected answers in the back. =]