6-2.......Algebra 2 Help, Please?

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2/8=1/4
X^2/X^6=1/X^4
Y^5/Y=Y^4
Z^-4/Z^3=1/Z^7

THEREFORE COMBINING THESE
ANSWER=Y^4/(4 X^4 Z^7)

choose letter c


those believe those who said d
but tell it to your classmates if they want to copy your homework...Show more

Everyone using PEMDAS and getting 9 seem to be making the same assumption that 6÷2(1+2) == (6÷2) * (1+2), whereas in fact you would get (6÷2)*1÷(1+2). If you treat it as a fraction PEMDAS becomes irrelevant and you can solve it in any order you like. 6÷2(1+2) ==6/ 2 * (1+2) == 6 * 1 / 2*(1+2) == 6 * 1/2 * 1/ (1+2) You can solve this is any order you like If you have complaints that there's fractions causing problems, take them out of the brackets 1st 6 / 2*1 + 2*2 = 6 / 2 + 4 = 6 / 6 = 1 or solve the brackets 1st then solve the denominator 6 / 2* (1+2) = 6/ 2* (3) = 6 / 6 = 1 If you want to treat the 6 ÷ 2 separately fine you just have to remember that a / b * c = a * (b * c)^-1 = a * b^-1 * c^-1 hence (6 / 2) * (1 + 2)^-1 = 3 * (1 + 2)^-1 = 3 ÷ (1 + 2) = 3 ÷ 3 = 1 You just have to remember the question is asking what is a÷b where a = 6 and b = 2(1+2), and that you cannot in any circumstances just move the (1+2) from the denominator to the numerator as this is solving the question, 6(1+2)÷2, which is completely different!...Show more

z^-4 in the numerator becomes z^4 in the denominator. So, we have: 2x^2 y^5/8x^6 y z^7.
Now divide both numerator and denominator by 2 x^2 y to get c) y^4/4x^4 z...Show more

Answer is c)
y^4/ 4x^4 z^7...Show more

2x^2 y^5 z^-4 / 8x^6 y z^3

2x^2 y^5 / 8x^6 y z^7

y^4 / 4x^4 z^7

which is C...Show more