Ok here’s one problems I have with AGW.?
According to the IPCC the simplified expression radiative forcing for CO2 is
http://www.grida.no/publications/other/ipcc_tar/?src=/climate/ipcc_tar/wg1/222.htm#tab62
(yahoo won't let me do the symbols correctly so I link to the IPCC report)
If I did my math correctly that means we should have warmed up by about 5c.
Since we haven't warmed up by anything close to that, did I do my math incorrectly, did the IPCC revise the math, is something else happening to prevent that forcing, or is the IPCC just wrong?
to James E
Did they correct this in the fourth assessment?
Its at 6.3.5 Simplified Expressions Table 6.2: scroll down a little and you'll see it.
OK here you go
C = 380
C0 = 280
Which give us
5.35*ln(380/280) = 1.63 Wm-2
Now 1 Watt is one Joule.second right?
365.25*24*60*60 = 31,557,600 number of seconds in a year (Note I use 365.25 to allow for leap year)
1.63 * 31,557,600 = 51,438,888
It takes 1,005 Joules to warm 1 kg air 1c
So 51,438,888/1005 = 51182.973
One-meter squared column of the atmosphere has a mass of 10,000kg
So 51182.973 / 10000 = 5.1182
Right?
to gcnp58
But wouldn't that just mean there would be a lot more evaporation and with water vapor being a green house gas cause even more warming, so shouldn't we be seen even more warming then the 0.78c that's been reported and would we be seeing a lot more rain, expectantly in area close to the ocean?
By the way I'm working out how much the ocean temperature should have risen assuming the numbers are close, but it's late so I'll work on it later.
Sorry it seems you already did, thanks.
To bucket22
No I didn’t get them from junkscience.com Steven Milloy, it was brought up in another board and they didn’t work it out they linked to the IPPC page and stated we should have warmed up by 5c. If they got it from junkscience.com they didn’t say, I worked out the math. That’s why I took the simplest formula :)
But if it’s from junkscience.com then they should at least get the credit for pointing this out, even if they are wrong. I’ll search for it and if I find it I’ll post a link.
Thanks.
Looks like you already found the link, thanks.
Just so you know here's the links I did use
I got the one watt = one joules from http://en.wikipedia.org/wiki/Watt
http://www.engineeringtoolbox.com/specific-heat-capacity-d_391.html
is where I got 1005 joules to raise the temp of 1 kg of air.
And the mass of a column of air I got from
http://onlinephys.com/pressure4.html
The last two links I got from online friends when I was working on this, had I known someone else had done the work it would have save me a lot of time.
To Keith P
I used 380 because it made the math simpler, I figured it would get me close, had I been way off from what that person had said I would have gone back and used 386. Like I said I’m trying to work out how much the ocean should have warmed, I know that it takes about 4,200 joules to warm one kg of water 1c and that the sun can only warm the top 100 meters. So now I’m working out how many kg or water in a column of water 1 meter sq by 100 meters. That is assuming the ocean will be absorbing the heat at the same rate as the formula says. That might be a faulty assumption, but I’ll work it out anyway.