I'm working on an IB portfolio for calculus and seem to be stumped by a simple problem. If I'm given 3=(square root of 2)^x, how do I solve for x? Do I just get the xth root of 3 = the square root of two? If I do, how do I solve from there?
tastethemat
Favorite Answer
make both sides of the equation into logs.
for example..
√5^x= 4
turns into
log√5^x= log4
and since x is the exponent it becomes
xlog√5 = log4
now you can solve for x.
x(log√5)/(log√5) = log4/(log√5)
x= log4/(log√5)
?
2^2.5 is additionally written with 2.5 in fraction style: 2^(5/2) In a extra usually happening style, this expression is the comparable as: ?(2^5) = ?32 = 4?2 ***In a fragment exponent, the denominator (backside extensive style) is the degree of the novel. in this occasion, with the aid of fact the denominator right it is two, then the novel has a capability of two, or a sq. root. The numerator (wonderful extensive style) will become the exponent of the backside extensive style, so in this occasion, the extensive style below the novel sign is two^5.