find the slope.. please help me.?
find the slope of the PERPENDICULAR BISECTOR of line AB
A (2,4)
B (-5,9)
find the slope of the PERPENDICULAR BISECTOR of line AB
A (2,4)
B (-5,9)
Rohn
Favorite Answer
slope (m) = increase in y / increase in x
m = (4 - 9) / (2 + 5) = -5 / 7
m = - 5/7
Any line perpendicular to this line would have slope of 7/5
Since multiplication of slope of 2 perpendicular lines equal -1
Using one of the point (2,4),
(y - 4) / (x - 2) = 7 / 5
5y - 20 = 7x -14
5y = 7x + 6 is the line perpendicular to that point
Rohn
TXR
slope (m) = (y2-y1)/(x2-x1)
(9-4)/(-5-2)
m = 5/-7
to find perpendicular bisector all you do is find the negative reciprocal, or 7/5
SISI
use this equation: y(2)-y(1)/x(2)-x(1) and plug in the numbers from the two points:
y(2)=9
y(1)=4
x(1)=-5
x(2)=2
your equation should look like 9-4/2-(-5)
Proud mother
ugh! i hate math in i'm in the 11th grade.