log (x) + log (x+2) = 1?

Favorite Answer

Wow, it's been a long time since I see a log problem ^^ thanks for sharing :D

I would do these steps:
log (x) + log (x+2) = 1
log (x+2) = 1 - log (x)
10^[log (x+2)] = 10^[1 - log (x)]
x + 2 = 10/x
x^2 + 2x - 10 = 0
solving this gives you (approx.)
x = 2.317 And x = - 4.317

But the negative one is not valid because the log of a negative doesn't exist ;)

So the final solution is *root*(11) - 1, which is approximately 2.317...Show more