How do you simpify/expand (2-(x/2))^2?

Wolfram Alpha says the answer is x^2/4 - 4, but I got the polar opposite, 4 - x^2/4 . Can you show me step by step how you would arrive to get x^2/4 - 4? I won't have Wolfram Alpha on a test, so I any help onto where I might have gone wrong would be greatly appreciated.

Thanks :-)

2011-02-02T13:32:13Z

Ah. I got it now. Thanks everyone~

V. Singh2011-02-02T13:25:14Z

Favorite Answer

[ 2 - (x/2) ] ^2 this is in the form of ( A - B )^2 = A^2 - 2AB + B^2, where A = 2 and B = x/2

[ 2 - (x/2) ] ^2 = 2^2 - 2*2*(x/2) + (x/2)^2
= 4 - 2x + x^2/4
= (x^2)/4 - 2x + 4
----------------------------------------------

Remember (a + b)^2 = a^2 + 2ab + b^2 and
................ (a - b)^2 = a^2 - 2ab + b^2

hope this helped

Vick

JOS J2011-02-02T21:19:49Z

4 - 2 x + x^2/4

?2011-02-02T21:26:01Z

Impossible The answer should be x^2/4-2x+4
Step1 write (2-x/2)*(2-x/2)
step2 multiply 2 then -x/2 like this: 2*(2-x/2)-x/2*(2-x/2)
equal 4-2x/2-2x/2+x^2/4 note that -x/2*-x/2 makes positive x^2/4
final answer by add the two -2x/2-2x/2 and dividing the 2 gives
4-2x-x^2/4 which u can write in any order

?2011-02-02T21:21:52Z

(a - b)^2 = (a - b)(a - b) = a^2 - 2ab + b^2
If a = 2, b = x/2
you get THREE terms
Two of them are x^2/4 and + 4
That should be enough help for you to finish this


Regards - Ian