How to find mol fraction if you are given Vapor pressure of solution and vapor pressure of h20? Plz help?

The problm is this:

A solution containing ethylene glycol and water has a vapor pressure of 7.88 torr @ 10 Celsius. Pure water has a vapor pressure of 9.21 torr @ 10 Celsius. What is the mole fraction of ethylene glycol in the solution??

I just cannot figure out how to set this problem up....I'm so lost :(

Dr.A2011-02-12T02:14:03Z

Favorite Answer

p = p°X
7.88 = 9.21 X

X = mole fraction water = 0.856
mole fraction ethylene glycol = 1 - 0.856=0.144

?2016-10-28T01:17:04Z

use roults regulation : PA=P`A*XA PB=P`B*XB P`A=vapour rigidity of the organic solvent(benzene) P`B=vapour rigidity of the organic solute(toluene) XA & XB are mole fractions of solvent & solute respectively...... as benzene & toluene make an suited answer,vapour rigidity over d soln. is P(T) P(T)=PA+ PB