given vapor pressure find mole fraction?

Using Algebra!

(a) What is the composition in mole fractions of a solution that has a vapor pressure of 40. torr at 20°C?

Let X be the mole fraction of benzene in this ideal solution. Thus 1-X is the mole fraction of toluene in this ideal solution.

The following is given:

75X + 22(1-X) = 40, or:

53X = 18, and X = 18/53.

Benzene's mole fraction is 18/53, and toluene's mole fraction is 35/53.

(b) What is the mole fraction of benzene in the vapor above the solution described in part (a)?

(75*18/53)/40 = 63.7%

Vapor Pressure Mole Fraction

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Hi bill! Your attempt is not correct. Convert from Torr to atm: 526/760 = 0.692 atm p solution = p water *Xwater p solution is the vapor pressure of the component in the mixture. p water is the vapor pressure of the pure component. Xwater is the molar fraction of the component in the mixture. p solution = 0.660 atm at 90 °C p water = 0.692 atm at 90 °C 0.660 = 0.692* Xwater Xwater = 0.660/0.692 = 0.954 Xwater + Xglucose = 1 Xglucose = 1 - Xwater Xglucose = 1 – 0.954 = 0.046 Answer: mol fraction of glucose = 0.046 at 90 °C Bye from Italy, C6H6 Signature: Asking is legitimate and choosing the Best Answer is good manners. Thank you.

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