How do you change x + 2y < -11 if x has no apparent slope other than 1,1?
How do you change x + 2y < -11 if x has no apparent slope other than 1,1? Do you write it as 2y > x -11 or 2y > 1x -11 ?
As in change I mean into slope-intercept form.
How do you change x + 2y < -11 if x has no apparent slope other than 1,1? Do you write it as 2y > x -11 or 2y > 1x -11 ?
As in change I mean into slope-intercept form.
oshkosh62
Favorite Answer
If you are given x + 2y < -11, and you are looking to get into slope-intercept form, you need to isolate the 'y'
So...
x + 2y < -11
-x -x
2y < -11 -x
Then divide by 2
y < (-11 - x) / 2
Or, if you need the slope:
y < (-11/2) - (x/2)
NOTE: The only time you change the sign (< or >) is if you *DIVIDE* by a negative.
So, if you had
x - y < 5
It would be:
-y < 5 -x
THEN :
y > -5 + x