expression for the de Broglie wavelength?

Find an expression for the de Broglie wavelength of an electron in the nth state of the hydrogen atom.
Express your answer in terms of some or all of the variables n, m, e, and appropriate constants.

DH2011-04-22T08:04:41Z

Favorite Answer

The de Broglie wavelength λ = h/mv where h = Planck' constant

Now mv = sqrt(2*m*K) and K = m*e^4/(εo^2*8*n^2*h^2)

So λ = h/sqrt(2*m* m*e^4/(εo^2*8*n^2*h^2)) = sqrt(8)*h^2*εo*n/(m*e^2*sqrt(2))

= 4*εo*n*h^2/(m*e^2)

durst2017-01-16T16:52:25Z

Expression For De Broglie Wavelength

Anonymous2016-11-19T04:12:00Z

(a) v = 0.480c = 0.480*3*(10^8) = one hundred forty four*(10^6) ms use ? = h ?mv the place ? is wavelength m is relax mass of electron = 9,a million*10^ -31kg v is the electron speed ? (gamma) is Lorenz component = a million sqrt( a million - v^2c^2 ) do it on your calculator it is the way I constantly use