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expression for the de Broglie wavelength?
Find an expression for the de Broglie wavelength of an electron in the nth state of the hydrogen atom.
Express your answer in terms of some or all of the variables n, m, e, and appropriate constants.
3 Answers
- DHLv 71 decade agoFavorite Answer
The de Broglie wavelength λ = h/mv where h = Planck' constant
Now mv = sqrt(2*m*K) and K = m*e^4/(εo^2*8*n^2*h^2)
So λ = h/sqrt(2*m* m*e^4/(εo^2*8*n^2*h^2)) = sqrt(8)*h^2*εo*n/(m*e^2*sqrt(2))
= 4*εo*n*h^2/(m*e^2)
- Anonymous4 years ago
(a) v = 0.480c = 0.480*3*(10^8) = one hundred forty four*(10^6) ms use ? = h ?mv the place ? is wavelength m is relax mass of electron = 9,a million*10^ -31kg v is the electron speed ? (gamma) is Lorenz component = a million sqrt( a million - v^2c^2 ) do it on your calculator it is the way I constantly use
