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Anonymous asked in Science & MathematicsPhysics · 5 days ago

What is the work needed to push a 500kg truck 800m up along a 5° incline with a coefficient of friction on the truck is 0.25?

Please help

2 Answers

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  • ?
    Lv 7
    5 days ago

    required work = increase in GPE + friction work

    W = mgd*sinΘ +µmgd*cosΘ = mgd*(sinΘ + µ*cosΘ)

    so W = 500kg * 9.8m/s² * 800m * (sin5º + 0.25*cos5º)

    W = 1.32x10⁶ J ◄ ..... or 1 MJ to one significant digit

  • oubaas
    Lv 7
    5 days ago

    work W = m*g*L*(sin 5°+cos 5°*μk) 

    W = 500*800*9.8*(0.0872+0.996*0.25) = 1.32*10^6 joule 

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