Solve for x... rational exponent x^(5/3) = 1-2x^2?
x^(5/3) = 1 - 2x^2
I've tried absolutely everything, I know it has 5 roots, 4 are imaginary, 1 is real.
I need to find the real value.
I've tried using x^(5/6)^2 as my ax^2 term, but it just doesn't fall out into anything nice.