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swincher4391
Lv 4
Solve for x... rational exponent x^(5/3) = 1-2x^2?
x^(5/3) = 1 - 2x^2
I've tried absolutely everything, I know it has 5 roots, 4 are imaginary, 1 is real.
I need to find the real value.
I've tried using x^(5/6)^2 as my ax^2 term, but it just doesn't fall out into anything nice.
1 Answer
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- Anonymous1 decade agoFavorite Answer
Solution: x ≈ 0.557723
http://www.wolframalpha.com/input/?i=x^%285%2F3%29...
Multiply each term by x³ and try to solve for x.
Good luck!
Source(s): Experience
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