How do you factor 27 - x^12?
It's a perfect cube, right? Please explain.
It's a perfect cube, right? Please explain.
Todd
Favorite Answer
Yes, it's a difference of cubes.
27 = 3^3
x^12 = (x^4)^3.
The general equation is (a-b)^3 = (a-b) * (a^2 + ab + b^2). Thus, we get
(3-x^4) * (9 + 3x^4 + x^8).
?
Difference of cubes: 27 = 3^3, x^12 = (x^4)^3
27 - x^12 = (3 - x^4) (9 + 3x^4 + x^8)
-- ÎαÏÏmÏm --
David
27 - x^12
(3 - x^4)(9 + 3x^4 + x^8)
Guillermo
- (x^4 - 3)*(x^8 + 3*x^4 + 9)
?
27 - X¹² = 3³ - (x⁴)³
= (3 - x⁴)[(x⁴)² + 3x⁴ + 3²]
= (3 - x⁴)(x⁸ + 3x⁴ + 9)