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Huggster
Huggster asked in Science & MathematicsMathematics · 10 years ago

How do you factor 27 - x^12?

It's a perfect cube, right? Please explain.

5 Answers

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  • Todd
    Lv 6
    10 years ago
    Favorite Answer

    Yes, it's a difference of cubes.

    27 = 3^3

    x^12 = (x^4)^3.

    The general equation is (a-b)^3 = (a-b) * (a^2 + ab + b^2). Thus, we get

    (3-x^4) * (9 + 3x^4 + x^8).

  • QC
    Lv 7
    10 years ago

    Difference of cubes: 27 = 3^3, x^12 = (x^4)^3

    27 - x^12 = (3 - x^4) (9 + 3x^4 + x^8)

    -- Ματπmφm --

  • David
    Lv 7
    10 years ago

    27 - x^12

    (3 - x^4)(9 + 3x^4 + x^8)

  • Guillermo
    Lv 7
    10 years ago

    - (x^4 - 3)*(x^8 + 3*x^4 + 9)

    Source(s): Maple 15
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  • Me
    Lv 7
    10 years ago

    27 - X¹² = 3³ - (x⁴)³

    = (3 - x⁴)[(x⁴)² + 3x⁴ + 3²]

    = (3 - x⁴)(x⁸ + 3x⁴ + 9)

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