If f(2)=2, and f(4)=5, what is x when f(x)=0.?

If f(2)=2, and f(4)=5, what is x when f(x)=0?
I skipped this question.

Ed I2011-12-03T09:02:31Z

Favorite Answer

m = (5 - 2)/(4 - 2) = 3/2

y - 2 = (3/2) (x - 2)
y - 2 = (3/2) x - 3
y = (3/2) x - 1 = f(x)

(3/2) x - 1 = 0
(3/2) x = 1
x = 2/3

I didn't skip this question.

MechEng20302011-12-03T17:17:18Z

Form an equation of a line from the two points:

m = (5 - 2)/(4 - 2) = 3/2

Eqn of line:

y - 5 = 3/2*(x - 4)

y = 3x/2 - 1

f(x) = 0 when x = 2/3

Iggy Rocko2011-12-03T17:07:29Z

Not enough information unless f is linear. Assuming f is linear, the slope of this line is
(2 - 5)/(2 - 4) = 3/2
Slope is also
(f(x) - 2)/(x - 2) = 3/2
(0 - 2)/(x - 2) = 3/2
-2/(x - 2) = 3/2
(x - 2)/(-2) = 2/3
x - 2 = -4/3
x = 2/3

Anonymous2011-12-03T17:11:49Z

You have left out some of the question!
If it is linear the previous answer does...
Suppose f(x)=x^2+bx+c
which is a perfectly good function
then 4+2b+c=2
and 16+4b+c=5
Solve for b and c
So f(0)=c