what´s the change in oxidation state in the corresponding C, iso-propanol is oxidized to acetone with KMno4?

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Isopropanol has the molecular formula of C3H8O and acetone has the molecular formula of (CH3)2CO. The KMnO4 really doesn't matter because there is no C in it, so we can ignore that bit of information.

Acetone carbon oxidation states:
Carbon number Attached atoms Sum of oxn nos of attached atoms C oxidation state
1 3H, 1C 3(+1) + 1(0) = +3 -3
2 2C, 1O 2(0) + 1(-2) = -2 +2
3 3H, 1C 3(+1) + 1(0) = +3 -3

2-Propanol carbon oxidation states:
Carbon number Attached atoms Sum of oxn nos of attached atoms C oxidation state
1 3H, 1C 3(+1) + 1(0) = +3 -3
2 2C, 1H, 1OH 2(0) + 1(+1) + 1(-1) = 0 0
3 3H, 1C 3(+1) + 1(0) = +3 -3

So there overall change in the oxidation numbers of C would be +2...Show more