Algebra 2 Inverse of Log Question?

I need help with my homework and I don't know how to solve it. But I have the answers.
Find the Inverse. (the ** symbol will mean the base number)

y=log*2* (-3x)

y=log*2* x+1

Answers to 1.y= -2^x/3 and 2. y= 2^x -1
Please explain how you got the answer. Thanks!!

Muntasir2012-02-01T19:10:18Z

By logorithm rules we take the base to the power of the answer then leave the leading sides

So for your first one
2^y = -3x
so divide both sides by 3
-2^y / 3 = x
Note the inverse means we plug the x for y
so y = -2^x/3

Try the second one with the same method

10

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