I'm curious about how i can solve an equation for lets say : y^2-y=x+4, in terms of something like y=" "
Or if you can tell me a specific mathematics topic that i can look into.
I am not looking for solutions, I want to be able to rewrite the function in terms of y(x)=
Paul
Favorite Answer
You could look into a topic called "completing the square".
Turn the left hand side into a perfect square
y^2 - y + (1/4) = x + 17/4
(y- 1/2)^2 = (4x + 17)/4
square root both sides
(y - 1/2) = sqrt((4x + 17)/4)
or (1/2-y) = sqrt((4x + 17)/4)
Let's take (y - 1/2) = sqrt((4x + 17)/4)
take the -1/2 term to rhs
y = 1/2 + sqrt((4x + 17)/4)
now take (1/2-y) = sqrt((4x + 17)/4)
add y to both sides
1/2 = y + sqrt((4x + 17)/4)
now subtract sqrt((4x + 17)/4) from both sides
1/2 - sqrt((4x + 17)/4) = y
so y = 1/2 - sqrt((4x + 17)/4) or 1/2 + sqrt((4x + 17)/4)
we could simplify it but you see how we solved for y.
Anonymous
y^2 - y = x + 4
(y - 1/2)^2 - 1/4 = x + 4
(y - 1/2)^2 = x + 17/4
y = 1/2 ± â(x + 17/4)
Nnj
Qardartic eqation
rahul mishra
the eqn u wrote is of parabola so i suggest u to read conic section