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Vf=Vi+at
46.1=18.5+a(2.47)
a(2.47)=46.1-18.5 , a=11.174 m/sec^2
D=1/2at^2+Vi *t
D=1/2(11.174)(2.47)^2+(18.5)(2.47)=79.78 m
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acceleration = ( Vf - Vi ) / t
acceleration = ( 46.1m/s - 18.5m/s ) / 2.47s
acceleration = ( 27.6m/s ) / 2.47s
acceleration = 11.2m/s^2
Distance = Vi*t + 0.5*a*t^2
Vi = 18.5m/s, t = 2.47s, a = 11.2m/s^2
Distance = ( 18.5m/s )*( 2.47s ) + 0.5*(11.2m/s^2 )*(2.47s)^2
Distance = 45.695m + 34.165m
Distance = 79.86m ~ 80m
So yeah, you're right....Show more