1) Suppose the coefficient of kinetic friction between m A and the plane is μk= 0.11, and that m A = m B = 2.7kg .
Figure available at http://session.masteringphysics.com/problemAsset/1057163/3/GIANCOLI.ch05.p030.jpg
A) As m B moves down, determine the magnitude of the acceleration of m A and m B, given theta = 32 degrees.
I AM LOST. PLEASE HELP!!
JullyWum
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My search for your link says web page not found.
Assuming mB hangs vertically (as masses are equal I'm using just m)
The weight component of A down the slope (mg sin32) and friction
(μ mg cos32) act against the motion of A up the slope.
The weight of B (mg) provides a force on A up the slope.
The net force acting in the system (Fn) is given by ..
Fn = mg↓ - (mg sin32 + μ mg cos32)↑
Fn= mg (1 - sin32 - μ cos32)
Fn = (2.70 x 9.80)(1 - sin32 - 0.11cos32) .. .. Fn = 9.97 N
The system has a net mass .. Mn = 5.40Kg (2 x 2.70)
Joint acceleration .. a = Fn / Mn
a = 9.97N / 5.40kg .. .. ►a = 1.85 m/s²
Anonymous
http://answers.yahoo.com/question/index;_ylt=AoRjeJf.YZnI1DCQ5VtIUDfty6IX;_ylv=3?qid=20121029214840AAKOYlM
Both Zorro and I have helped with this problem...I think its your ignorance...
If the answer is wrong plz comment and I will work out again...
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His Activity...
http://answers.yahoo.com/activity;_ylt=Amdb9XpQgIIfGcHMa7V.m_zsy6IX;_ylv=3?show=Q9SSZMIuaa&link=question#yan-questions-answer
The question answered by me :]
http://answers.yahoo.com/question/index;_ylt=Aoux7BntKyr0D6t2m7Ia.dzsy6IX;_ylv=3?qid=20121029214840AAKOYlM