DR. ZORRO OR SOMEONE PLEASE HELP?

My search for your link says web page not found.

Assuming mB hangs vertically (as masses are equal I'm using just m)

The weight component of A down the slope (mg sin32) and friction

(μ mg cos32) act against the motion of A up the slope.

The weight of B (mg) provides a force on A up the slope.

The net force acting in the system (Fn) is given by ..

Fn = mg↓ - (mg sin32 + μ mg cos32)↑

Fn= mg (1 - sin32 - μ cos32)

Fn = (2.70 x 9.80)(1 - sin32 - 0.11cos32) .. .. Fn = 9.97 N

The system has a net mass .. Mn = 5.40Kg (2 x 2.70)

Joint acceleration .. a = Fn / Mn

a = 9.97N / 5.40kg .. .. ►a = 1.85 m/s²

http://answers.yahoo.com/question/index;_ylt=AoRje...

Both Zorro and I have helped with this problem...I think its your ignorance...

If the answer is wrong plz comment and I will work out again...

Sorry My bad but I think he can check his activity..Not only Dr.Zorro or me have helped him with this question...Its his plain ignorance...All the question he asked is the same and most of them are answered..

His Activity...

http://answers.yahoo.com/activity;_ylt=Amdb9XpQgII...

The question answered by me :]

http://answers.yahoo.com/question/index;_ylt=Aoux7...