Simple chemistry gas law question? Im so confused?

I really don't know where to start. I know that Boyles alw is p1v1 = k ......p2v2=K and that p1v1 = p2v2

A certain gas is present in a 12.0L cylinder at 2.0atm pressure. If the pressure is increased to 4.0atm , the volume of the gas decreases to 6.0L . Find the two constants ki, the initial value of k, and kt the final value of k, to verify whether the gas obeys Boyle’s law.

Trevor H2013-05-03T11:50:24Z

Favorite Answer

In the first condition:
P1 = 2.0atm
V1 = 12.0L
P1V1 = Ki
2*12 = Ki
Ki = 24

In the second condition
Pt = 4.0atm
Vt = 6.0L
Pt*Vt = Kt
4.0*6.0 = Kt
Kt = 24

Conclusion : Ki = Kt .
Gas obeys Boyle's Law.