C++ how to take user input of time and seperate it into hours and minutes?

Question

I need to take a users input such as 10:35 and put it into a variable of hours and minutes. How can I do this using the colon as the separate for the two? This is how the assignment requires it be entered.

Example of what I am doing.

int main()
{
char again = 'y';
int userHours = 0;
int userMinutes = 0;

while (again == 'y')
{
cout << "Enter a time in 24-hour notation: ";
cin >> userHours >> ":" >> userMinutes;
}
return 0;
}

2014-03-04T04:19:51Z

Actually I already solved it thanks to the people on stackoverflow. Just need a variable for the colon, so I just added the lines.

char colon;

cin >> userHours >> colon >> userMinutes;

cja · Accepted Answer

You should do something like this:

#include <iostream>
#include <string>
#include <sstream>
#include <iomanip>

using namespace std;

const char delim = ':';
const unsigned hoursPerDay = 24;
const unsigned minutesPerHour = 60;

int main(int argc, char *argv[]) {
string in;
stringstream ss;
unsigned hours, minutes;
char c;

while (true) {
cout << "Enter time (HH" << delim << "MM) : ";
getline(cin,in);
ss.clear(); ss.str(in);
if ((ss >> hours >> c >> minutes) &&
(c == delim) &&
(hours < hoursPerDay) &&
(minutes < minutesPerHour)) {
cout << setw(2) << setfill('0') << hours << delim
<< setw(2) << setfill('0') << minutes << endl;
}
}
return 0;
}

#if 0

Sample run:

Enter time (HH:MM) : 13:45
13:45
Enter time (HH:MM) : 12
Enter time (HH:MM) : 9:09
09:09

#endif

C++ how to take user input of time and seperate it into hours and minutes?

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