C++ how to take user input of time and seperate it into hours and minutes?

Question

I need to take a users input such as 10:35 and put it into a variable of hours and minutes. How can I do this using the colon as the separate for the two? This is how the assignment requires it be entered.

Example of what I am doing.

int main()

{

char again = 'y';

int userHours = 0;

int userMinutes = 0;

while (again == 'y')

{

cout << "Enter a time in 24-hour notation: ";

cin >> userHours >> ":" >> userMinutes;

}

return 0;

}

Update:

Actually I already solved it thanks to the people on stackoverflow. Just need a variable for the colon, so I just added the lines.

char colon;

cin >> userHours >> colon >> userMinutes;

cja · Accepted Answer

You should do something like this:

#include <iostream>

#include <string>

#include <sstream>

#include <iomanip>

using namespace std;

const char delim = ':';

const unsigned hoursPerDay = 24;

const unsigned minutesPerHour = 60;

int main(int argc, char *argv[]) {

string in;

stringstream ss;

unsigned hours, minutes;

char c;

while (true) {

cout << "Enter time (HH" << delim << "MM) : ";

getline(cin,in);

ss.clear(); ss.str(in);

if ((ss >> hours >> c >> minutes) &&

(c == delim) &&

(hours < hoursPerDay) &&

(minutes < minutesPerHour)) {

cout << setw(2) << setfill('0') << hours << delim

<< setw(2) << setfill('0') << minutes << endl;

}

return 0;

}

#if 0

Sample run:

Enter time (HH:MM) : 13:45

13:45

Enter time (HH:MM) : 12

Enter time (HH:MM) : 9:09

09:09

#endif

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C++ how to take user input of time and seperate it into hours and minutes?

1 Answer