Three identical point charges in an equilateral triangle.?
Q = +3uC
What are the magnitude and direction of the net electric force on the charge in the lower left side. The side of the triangle is 0.1 m.
Q = +3uC
What are the magnitude and direction of the net electric force on the charge in the lower left side. The side of the triangle is 0.1 m.
Woodsman
Favorite Answer
For each charge pair,
F = kQq / d² = 8.99e9 N·m²/C² * (3e-6C)² / (0.1m)² = 8.1 N
Due to symmetry the net force on each particle clearly has a direction that passes from the center of the triangle through the particle.
Therefore the magnitude of the force on each particle is
F = 2 * 8.1N * cos30º = 14 N
Θ = 30º below horizontal (210º from +x axis)