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Three identical point charges in an equilateral triangle.?
Q = +3uC
What are the magnitude and direction of the net electric force on the charge in the lower left side. The side of the triangle is 0.1 m.
1 Answer
- WoodsmanLv 77 years agoFavorite Answer
For each charge pair,
F = kQq / d² = 8.99e9 N·m²/C² * (3e-6C)² / (0.1m)² = 8.1 N
Due to symmetry the net force on each particle clearly has a direction that passes from the center of the triangle through the particle.
Therefore the magnitude of the force on each particle is
F = 2 * 8.1N * cos30º = 14 N
Θ = 30º below horizontal (210º from +x axis)
