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Need to know about how forces are being balanced?
I am learning physics and trying to understand the concept about forces.
if the 20 KG block is bringing the string further down and the spring is changing from (Xo to Xf).
how is the forces is being balanced?
is there any force being applied on the pulley?
1 Answer
- ?Lv 75 days ago
According to Hooke's Law, the spring force is equal to
F = k*(Xf - Xo). At equilibrium, the spring force will equal the weight of the hanging mass (assuming an ideal pulley -- but that's a whole other subject).
At equilibrium, the tension above the 20 kg mass is
F = 20kg * g ≈ 200 N
The balancing force on the left side of the pulley is
F = 200 N = k*(Xf-Xo) + 4kg * g = k*(Xf-Xo) * 40N
which tells us that the spring force is around 160 N.
So there is a force of 400 N down on the pulley. There must be a force of 400 N upward on the pulley provided by the ceiling.
Similarly, there must be a force of 160 N pulling down on the spring at the ground.
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