Three identical point charges in an equilateral triangle.?
Q = +3uC
What are the magnitude and direction of the net electric force on the charge in the lower left side. The side of the triangle is 0.1 m.
Q = +3uC
What are the magnitude and direction of the net electric force on the charge in the lower left side. The side of the triangle is 0.1 m.
billrussell42
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here is a similar Q/A, just plug in the numbers
Question: Three equal charges are placed at the corners of an equilateral triangle. What is the force on each?
Ans: The forces on each are equal from symmetry and are pointing directly away from the midpoint of the opposite side. D is the length of a side of the triangle.
The Force from one charge to either of the others is
F = kQ²/D²
From symmetry, the force is on a line bisecting the opposite side. The components orthogonal to that line cancel, so the net force from each is
F = (1/√2)kQ²/D² = (√2/2)kQ²/D²
Adding the forces from the two charges, that is
F = (√2)kQ²/D²
Coulomb's law, force of attraction/repulsion
F = kQ₁Q₂/r²
Q₁ and Q₂ are the charges in coulombs
r is separation in meters
k = 8.99e9 Nm²/C²