Three identical point charges in an equilateral triangle.?

here is a similar Q/A, just plug in the numbers

Question: Three equal charges are placed at the corners of an equilateral triangle. What is the force on each?

Ans: The forces on each are equal from symmetry and are pointing directly away from the midpoint of the opposite side. D is the length of a side of the triangle.

The Force from one charge to either of the others is

F = kQ²/D²

From symmetry, the force is on a line bisecting the opposite side. The components orthogonal to that line cancel, so the net force from each is

F = (1/√2)kQ²/D² = (√2/2)kQ²/D²

Adding the forces from the two charges, that is

F = (√2)kQ²/D²

Coulomb's law, force of attraction/repulsion

F = kQ₁Q₂/r²

Q₁ and Q₂ are the charges in coulombs

r is separation in meters

k = 8.99e9 Nm²/C²