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A box starts falling from the top of a plane inclined 10º above horizontal. The coefficient of kinetic friction is 0.2. What?
A box starts falling from the top of a plane inclined 10º above horizontal. The coefficient of kinetic friction is 0.2. What will be the speed of the mass after sliding 3 m along the plane?
Can someone please explain this? I dont know what to do and have a test tomorrow, thanks.
1 Answer
- ?Lv 75 days agoFavorite Answer
sin 10° = 0.174
cos 10° = 0.985
g = 9.8 m/sec^2
Δh = L*sin 10° = 0.174*3 = 0.52 m
ΔGPE = Δh*m*g
ΔGPE = m*g*cos 10°*μk*L+m/2*V^2
0.52*9.8*m = m(9.8*0.985*0.2*3+V^2/2)
mass m cancels
5.10-5.7 ......it becomes negative ; i.e. the box won't move
check : tan 10° = 0.18 = μk max for having motion ; if μk > 0.18, the box stays at rest
