find the relative max/min and absolute max/min in the graph y=2/(x-1)?

Question

please help i dont understand

Viola · Answer

There is none, only asymptotes at x = 1 and y = 0.

cidyah · Answer

f(x) = 2/(x-1)
x=1 is a point of discontinuity

f'(x) = -2/(x-1)^2 
f'(x) is undefined when x=1
x=1 is a critical point

There is no relative maximum or minimum

Brainard · Answer

This graph has no max/min
 
For y to have max/min,  y '   has to be equal to 0

y '   =  -2/(x - 1)^2 and this is negative for all values of x, but never 0

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