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find the relative max/min and absolute max/min in the graph y=2/(x-1)?

please help i dont understand

3 Answers

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  • Viola
    Lv 5
    7 years ago

    There is none, only asymptotes at x = 1 and y = 0.

  • cidyah
    Lv 7
    7 years ago

    f(x) = 2/(x-1)

    x=1 is a point of discontinuity

    f'(x) = -2/(x-1)^2

    f'(x) is undefined when x=1

    x=1 is a critical point

    There is no relative maximum or minimum

  • 7 years ago

    This graph has no max/min

    For y to have max/min, y ' has to be equal to 0

    y ' = -2/(x - 1)^2 and this is negative for all values of x, but never 0

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