A block of wood of mass 24 kg floats in water. The volume of wood is 0.032 m^3. Find a)the volume of the block below the surface of water.?

2014-09-17T03:44:11Z

b)the density of wood

The vol of water is 1000 kg m^3

GF2014-09-17T03:57:14Z

Favorite Answer

I will try:

density of fluid * Volume submerged = density of object * volume of object
Volume submerged = density of object * vol of object / density of fluid
= {(24/0.032) * 0.032} / 1000
= 0.024 m^3

Note that the displaced water is to support 24 kg is: 24/1000 = 0.024 m^3

oubaas2014-09-17T04:52:30Z

wood density ρ = 24/32 = 0,75 kg/dm^3
Vi = V*ρ = 32*3/4 = 24 dm^3
Ve = V(1-ρ) = 32*0.25 = 8 dm^3