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A block of wood of mass 24 kg floats in water. The volume of wood is 0.032 m^3. Find a)the volume of the block below the surface of water.?
b)the density of wood
The vol of water is 1000 kg m^3
2 Answers
- ?Lv 67 years agoFavorite Answer
I will try:
density of fluid * Volume submerged = density of object * volume of object
Volume submerged = density of object * vol of object / density of fluid
= {(24/0.032) * 0.032} / 1000
= 0.024 m^3
Note that the displaced water is to support 24 kg is: 24/1000 = 0.024 m^3
- oubaasLv 77 years ago
wood density ρ = 24/32 = 0,75 kg/dm^3
Vi = V*ρ = 32*3/4 = 24 dm^3
Ve = V(1-ρ) = 32*0.25 = 8 dm^3
